When DataGridView is attached to a binding source that is linked to an EF4 Entity, how do you sort it?

c# datagridview entity-framework sorting winforms


I have a DataGridView that is linked to a BindingSource.

My BindingSource is linked to an IQueryable list of entities:

    public void BindTo(IQueryable elements)
        BindingSource source = new BindingSource();
        source.DataSource = elements;

        bindingNavigator1.BindingSource = source;
        dataGridView1.DataSource = source;


I am wanting my users to be able to click on the grid headers to sort the data - struggling to get this to work. Is it possible? If so, how do I do it?

5/2/2013 2:14:23 PM

Accepted Answer

I recently struggled with this same issue; it seems that the IQueryable interface doesn't provide enough information for the DataViewGrid to know how to sort the data automatically; so you have to either repackage your collection from the Entity source using something it can use or do what I did and handle the sorting functionality manually:

      private void myDataGridView_ColumnHeaderMouseClick(object sender, DataGridViewCellMouseEventArgs e)
     DataGridViewColumn column = myDataGridView.Columns[e.ColumnIndex];

     _isSortAscending = (_sortColumn == null || _isSortAscending == false);

     string direction = _isSortAscending ? "ASC" : "DESC";

     myBindingSource.DataSource = _context.MyEntities.OrderBy(
        string.Format("it.{0} {1}", column.DataPropertyName, direction)).ToList();

     if (_sortColumn != null) _sortColumn.HeaderCell.SortGlyphDirection = SortOrder.None;
     column.HeaderCell.SortGlyphDirection = _isSortAscending ? SortOrder.Ascending : SortOrder.Descending;
     _sortColumn = column;

I hope that helps.

12/16/2010 5:38:21 PM

Popular Answer

This code snippet works very well, and fast enough for most purposes...

int iColNumber = 3; //e.g., sorting on the 3rd column of the DGV

MyBindingSource.DataSource = MyBindingList.OrderByDescending(o => o.GetType().GetProperty(MyDataGridView.Columns[iColNumber].Name).GetValue(o));

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